(4x^2-x+5)+(2x^2+x-7)=0

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Solution for (4x^2-x+5)+(2x^2+x-7)=0 equation:


Simplifying
(4x2 + -1x + 5) + (2x2 + x + -7) = 0

Reorder the terms:
(5 + -1x + 4x2) + (2x2 + x + -7) = 0

Remove parenthesis around (5 + -1x + 4x2)
5 + -1x + 4x2 + (2x2 + x + -7) = 0

Reorder the terms:
5 + -1x + 4x2 + (-7 + x + 2x2) = 0

Remove parenthesis around (-7 + x + 2x2)
5 + -1x + 4x2 + -7 + x + 2x2 = 0

Reorder the terms:
5 + -7 + -1x + x + 4x2 + 2x2 = 0

Combine like terms: 5 + -7 = -2
-2 + -1x + x + 4x2 + 2x2 = 0

Combine like terms: -1x + x = 0
-2 + 0 + 4x2 + 2x2 = 0
-2 + 4x2 + 2x2 = 0

Combine like terms: 4x2 + 2x2 = 6x2
-2 + 6x2 = 0

Solving
-2 + 6x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 6x2 = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 6x2 = 0 + 2
6x2 = 0 + 2

Combine like terms: 0 + 2 = 2
6x2 = 2

Divide each side by '6'.
x2 = 0.3333333333

Simplifying
x2 = 0.3333333333

Take the square root of each side:
x = {-0.577350269, 0.577350269}

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